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Deduce reference return type in approx() 

By default, lambdas deduce the return type as a value type, not a
reference.
This commit is contained in:
Marc Glisse 2020-03-31 21:02:32 +02:00
parent 23aca30a04
commit fe3ff9c19f
1 changed files with 2 additions and 2 deletions
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4
Filtered_kernel/include/CGAL/Lazy.h
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@ -116,9 +116,9 @@ template<class T>inline std::enable_if_t<std::is_empty<T>::value, unsigned> dept
// For an iterator, exact/approx applies to the objects it points to
template <class T, class=std::enable_if_t<is_iterator_type<T,std::input_iterator_tag>::value>>
auto exact(T const& t) {return make_transforming_iterator(t,[](auto const&u){return CGAL::exact(u);});}
auto exact(T const& t) {return make_transforming_iterator(t,[](auto const&u)->decltype(auto){return CGAL::exact(u);});}
template <class T, class=std::enable_if_t<is_iterator_type<T,std::input_iterator_tag>::value>>
auto approx(T const& t) {return make_transforming_iterator(t,[](auto const&u){return CGAL::approx(u);});}
auto approx(T const& t) {return make_transforming_iterator(t,[](auto const&u)->decltype(auto){return CGAL::approx(u);});}
template <class T, class=std::enable_if_t<is_iterator_type<T,std::input_iterator_tag>::value>>
unsigned depth(T const&) {return 1;} // FIXME: depth(*t) would be better when t is valid, but not for end iterators, and the true answer would iterate on the range, but we can't do that with only one iterator... We need to replace iterators with ranges to solve that.